##### Asked by: Marinov Enzo

asked in category: General Last Updated: 20th January, 2020# What is the oxidation number of chromium in nh4 2Cr2O7?

**oxidation number of chromium**(

**Cr) in (NH4**)

**2Cr2O7**is (+6).

Also know, what is the oxidation number of chromium in ammonium dichromate?

**Ammonium dichromate** is an inorganic compound with the formula (NH_{4})_{2}**Cr**_{2}O_{7}. In this compound, as in all chromates and dichromates, **chromium** is in a +6 **oxidation state**, commonly known as hexavalent **chromium**.

Additionally, what is the charge of CR in cr2o7? The sum of the oxidation numbers in Cr2O72-, a polyatomic ion, is -2, the **charge** of the ion. We assign -2 as the **oxidation number** for each oxygen, and x as the **oxidation number** of each **chromium** and write the following equation: 2x + 7(-2) = - 2… x = +6.

Keeping this in consideration, what is oxidation number of nh4?

Answer: **NH4** has +1 charge the **oxidation state** or **number** of nitrogen is -3 and hydrogen has +1. So the overall change is +1.

What is the oxidation number of nitrogen in nh4 2so4?

The total charge on sulphate ion is -2 , hence the total charge on ammonium ion (**NH4**)2 should be +2. Total charge on a single ammonium ion (**NH4**) is +1. Solving the equation will give the **oxidation state of nitrogen** - 3 and not 1.