Asked by: Marinov Enzo
asked in category: General Last Updated: 20th January, 2020

What is the oxidation number of chromium in nh4 2Cr2O7?

In conclusion, the oxidation number of chromium (Cr) in (NH4)2Cr2O7 is (+6).

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Also know, what is the oxidation number of chromium in ammonium dichromate?

Ammonium dichromate is an inorganic compound with the formula (NH4)2Cr2O7. In this compound, as in all chromates and dichromates, chromium is in a +6 oxidation state, commonly known as hexavalent chromium.

Additionally, what is the charge of CR in cr2o7? The sum of the oxidation numbers in Cr2O72-, a polyatomic ion, is -2, the charge of the ion. We assign -2 as the oxidation number for each oxygen, and x as the oxidation number of each chromium and write the following equation: 2x + 7(-2) = - 2… x = +6.

Keeping this in consideration, what is oxidation number of nh4?

Answer: NH4 has +1 charge the oxidation state or number of nitrogen is -3 and hydrogen has +1. So the overall change is +1.

What is the oxidation number of nitrogen in nh4 2so4?

The total charge on sulphate ion is -2 , hence the total charge on ammonium ion (NH4)2 should be +2. Total charge on a single ammonium ion (NH4) is +1. Solving the equation will give the oxidation state of nitrogen - 3 and not 1.

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